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[백준] 미로 탐색(2178)(Kotlin)

by 유줘니 2020. 1. 22.

원본 문제 : https://www.acmicpc.net/problem/2178

문제 참고 : https://zoonvivor.tistory.com/77

 

<첫번째>

import java.io.*
import java.util.*

var arr: Array<IntArray> = arrayOf()
var visited: Array<BooleanArray> = arrayOf()
var dx: IntArray = intArrayOf(-1,0,1,0)
var dy: IntArray = intArrayOf(0,-1,0,1)
var N: Int = 0
var M: Int = 0

data class Dot(var x: Int, var y: Int)

fun main() = with(BufferedReader(InputStreamReader(System.`in`))) {

    val input = readLine().split(" ")
    N = input[0].toInt()
    M = input[1].toInt()

    arr = Array(N) { IntArray(M) }
    visited = Array(N) { BooleanArray(M) }

    for ( i in 0 until N ) {
        val str = readLine()
        for ( j in 0 until M ) {
            arr[i][j] = (str[j]+"").toInt()
            visited[i][j] = false
        }
    }

    visited[0][0] = true
    bfs(0, 0)
    println(arr[N-1][M-1])

}

fun bfs(x: Int, y: Int) {
    val queue: Queue<Dot> = LinkedList<Dot>()
    queue.add(Dot(x, y))

    while ( !queue.isEmpty() ) {
        val d: Dot = queue.poll()

        for ( i in 0 until 4 ) {
            val nX = d.x + dx[i]
            val nY = d.y + dy[i]

            if ( nX < 0 || nY < 0 || nX >= N || nY >= M )
                continue
            if ( visited[nX][nY] || arr[nX][nY] == 0 )
                continue

            queue.add(Dot(nX, nY))
            arr[nX][nY] = arr[d.x][d.y] + 1
            visited[nX][nY] = true
        }
    }
}

 

<두번째> 2020/06/09

import java.io.BufferedReader
import java.io.InputStreamReader
import java.util.*

var matrix: Array<IntArray> = arrayOf()
var visited: Array<BooleanArray> = arrayOf()
var nm: List<Int> = listOf()

data class Dot(val x: Int, val y: Int)

fun main() = with(BufferedReader(InputStreamReader(System.`in`))) {

    nm = readLine().split(" ").map { it.toInt() }
    matrix = Array(nm[0]) { IntArray(nm[1]) }
            .map { readLine().map{ it.toInt() - 48 }.toIntArray()
            }.toTypedArray()
    visited = Array(nm[0]) { BooleanArray(nm[1]) { false } }

    visited[0][0] = true
    bfs(0, 0)
    println(matrix[nm[0] - 1][nm[1] - 1])

}

fun bfs(x: Int, y: Int) {
    val dx = intArrayOf(1,-1,0,0)
    val dy = intArrayOf(0,0,-1,1)
    val list: LinkedList<Dot> = LinkedList()
    list.add(Dot(x, y))

    while (list.isNotEmpty()) {

        val now = list.poll()

        for (i in 0 until 4) {
            val nx = now.x + dx[i]
            val ny = now.y + dy[i]

            if (nx !in 0 until nm[0] || ny !in 0 until nm[1]) continue
            if (matrix[nx][ny] == 0 || visited[nx][ny]) continue

            list.add(Dot(nx, ny))
            matrix[nx][ny] = matrix[now.x][now.y] + 1
            visited[nx][ny] = true

        }
    }
}

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